字符串是ex="test1,test2,test3,test4,test5"当我使用ex.split(",").first返回"test1"现在我想获取剩余的项目,即“test2、test3、test4、test5”。如果我使用ex.split(",").last它只返回"test5"如何让所有剩余的项目跳过第一个? 最佳答案 试试这个:first,*rest=ex.split(/,/)现在first将是第一个值,rest将是数组的其余部分。 关于ruby-如何在Ruby中拆分字符串并获
我目前有一个运行大约200次的函数。函数如下所示:functionGetB(av,bol){varbxes=[["11","12","13","21","22","23","31","32","33"],["14","15","16","24","25","26","34","35","36"],["17","18","19","27","28","29","37","38","39"],["41","42","43","51","52","53","61","62","63"],["44","45","46","54","55","56","64","65","66"],["47",